# Covariant formulation of classical electromagnetism: Wikis

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Electromagnetism
Electricity · Magnetism

The covariant formulation of classical electromagnetism refers to ways of writing the laws of classical electromagnetism (in particular, Maxwell's equations and the Lorentz force) in a form which is "manifestly covariant" (i.e. in terms of covariant four-vectors and tensors), in the formalism of special relativity. These expressions both make it simple to prove that the laws of classical electromagnetism take the same form in any inertial coordinate system, and also provide a way to translate the fields and forces from one frame to another.

The Minkowski metric used in this article is assumed to have the form diag (-1, +1, +1, +1). The purely spatial components of the tensors (including vectors) are given in SI units. This article uses the classical treatment of tensors and the Einstein summation convention throughout. Where the equations are specified as holding in a vacuum, one could instead regard them as the formulation of Maxwell's equations in terms of total charge and current.

For a more general overview of the relationships between classical electromagnetism and special relativity, including various conceptual implications of this picture, see the article: Classical electromagnetism and special relativity.

## Covariant objects

### Electromagnetic tensor

The electromagnetic tensor is the combination of the electric and magnetic fields into a covariant antisymmetric tensor. In volt·seconds/meter2, the field strength tensor is written in terms of fields as:

$F_{\alpha \beta} = \left( \begin{matrix} 0 & \frac{E_x}{c} & \frac{E_y}{c} & \frac{E_z}{c} \ \frac{-E_x}{c} & 0 & -B_z & B_y \ \frac{-E_y}{c} & B_z & 0 & -B_x \ \frac{-E_z}{c} & -B_y & B_x & 0 \end{matrix} \right)$

and the result of raising its indices is

$F^{\mu \nu} \, \stackrel{\mathrm{def}}{=} \, \eta^{\mu \alpha} \, F_{\alpha \beta} \, \eta^{\beta \nu} = \left( \begin{matrix} 0 & \frac{-E_x}{c} & \frac{-E_y}{c} & \frac{-E_z}{c} \ \frac{E_x}{c} & 0 & -B_z & B_y \ \frac{E_y}{c} & B_z & 0 & -B_x \ \frac{E_z}{c} & -B_y & B_x & 0 \end{matrix} \right).$
where
E is the electric field,
B the magnetic field, and
c the speed of light.
Caution: The signs in the tensor above depend on the convention used for the metric tensor. The convention used here is +---, corresponding to the metric tensor:
$\begin{pmatrix} 1 & 0 & 0 & 0 \\ 0 & -1 & 0 & 0 \\ 0 & 0 & -1 & 0 \\ 0 & 0 & 0 & -1 \end{pmatrix}$

### Four-Current

The four-current is the contravariant four-vector which combines electric current and electric charge density. In amperes/meter2, it is given by

$J^{\alpha} = \, (c \rho, \mathbf{J} )$

where ρ is the charge density, $\mathbf{J}$ is the current density, and c is the speed of light.

### Four-potential

In volt·seconds/meter, the electromagnetic four-potential is a covariant four-vector containing the electric potential and magnetic vector potential, as follows:

$A_{\alpha} = \left( - \phi/c, \mathbf{A} \right)$

where φ is the scalar potential and $\mathbf{A}$ is the vector potential.

The relation between the electromagnetic potentials and the electromagnetic fields is given by the following equation:

$F_{\alpha \beta} = \partial_{\alpha} A_{\beta} - \partial_{\beta} A_{\alpha} \,$

where

$\partial_\alpha = \frac{\partial}{\partial x^{\alpha}} = \left( \frac{1}{c} \frac{\partial}{\partial t}, \mathbf{\nabla} \right) \,.$

### Electromagnetic stress-energy tensor

The electromagnetic stress-energy tensor is a contravariant symmetric tensor which is the contribution of the electromagnetic fields to the overall stress-energy tensor. In joules/meters3, it is given by

$T^{\alpha\beta} = \begin{bmatrix} \frac{1}{2}(\epsilon_{0}E^2 + \frac{1}{\mu_{0}}B^2) & S_x/c & S_y/c & S_z/c \\ S_x/c & -\sigma_{xx} & -\sigma_{xy} & -\sigma_{xz} \ S_y/c & -\sigma_{yx} & -\sigma_{yy} & -\sigma_{yz} \ S_z/c & -\sigma_{zx} & -\sigma_{zy} & -\sigma_{zz} \end{bmatrix}$

where ε0 is the electric permittivity of vacuum, μ0 is the magnetic permeability of vacuum, the Poynting vector is

$\mathbf{S} = \frac{1}{\mu_{0}} \mathbf{E} \times \mathbf{B} \,$

and the Maxwell stress tensor is given by

$\sigma_{ij} = \epsilon_{0}E_{i}E_{j} + \frac{1}{\mu_{0}}B_{i}B_{j} - \tfrac{1}{2}(\epsilon_{0}E^2 + \frac{1}{\mu_{0}}B^2)\delta_{ij} \,.$

The electromagnetic stress-energy tensor is related to the electromagnetic field tensor by the equation:

$T^{\alpha\beta} = \frac{-1}{\mu_{0}} ( F^{\alpha \gamma}\eta_{\gamma \nu}F^{\nu \beta} + \frac{1}{4}\eta^{\alpha\beta}F_{\gamma \nu}F^{\gamma \nu})$

where $\eta \,$ is the Minkowski metric tensor. Notice that we use the fact that

$\epsilon_{0} \mu_{0} c^2 = 1\,.$

### Other, non-electromagnetic objects

For background purposes, we present here three other relevant four-vectors, which are not directly connected to electromagnetism, but which will be useful in this article:

• In meters, the "position" or "coordinate" four-vector is
$x^\alpha = (ct, x, y, z) \,.$
$u^\alpha = \gamma(c,\mathbf{u}) \,$
where $\mathbf{u} \,$ is the (three-vector) velocity and $\gamma \,$ is the Lorentz factor associated with $\mathbf{u} \,.$
$p_\alpha = (- E/c, \mathbf{p}) = m \, \eta_{\alpha \nu} \, u^{\nu} \,$
where $\mathbf{p} \,$ is the (three-vector) momentum, E is the energy, and m is the particle's rest mass.

## Maxwell's equations

In a vacuum, Maxwell's equations can be written as two tensor equations

$\frac{\partial F^{\beta \alpha}}{\partial x^\alpha} = \mu_{0} J^\beta \qquad\hbox{and}\qquad 0 = \epsilon^{\alpha \beta \gamma \delta} \frac{\partial F_{\alpha \beta}}{\partial x^\gamma}$

where F αβ is the electromagnetic tensor, J α is the 4-current, є αβγδ is the Levi-Civita symbol (a mathematical construct), and the indices behave according to the Einstein summation convention.

The first tensor equation is an expression of the two inhomogeneous Maxwell's equations, Gauss's Law and Ampere's Law (with Maxwell's correction). The second equation is an expression of the homogeneous equations, Faraday's law of induction and Gauss's law for magnetism.

In the absence of sources, Maxwell's equations reduce to a wave equation in the field strength:

$\eta^{\gamma \nu} \partial_{\gamma} \partial_{\nu} F^{\alpha\beta} \, \stackrel{\mathrm{def}}{=} \, \Box F^{\alpha\beta} \, \stackrel{\mathrm{def}}{=} \, \nabla^2 F^{\alpha\beta} - {1 \over c^2 } { \partial^2 F^{\alpha\beta} \over {\partial t }^2 } = 0 \,.$

Here, $\Box$ is the d'Alembertian operator.

### Other notation

Without the summation convention or the Levi-Civita symbol, the equations would be written

$\sum_{x^\alpha =ct,x,y,z}{\partial F^{\beta \alpha}\over\partial x^\alpha} = \mu_{0} J^{\beta} \qquad\hbox{and}\qquad 0 = {\partial F_{\alpha\beta}\over\partial x^\gamma} + {\partial F_{\beta\gamma}\over\partial x^\alpha} + {\partial F_{\gamma\alpha}\over\partial x^\beta}$

where all indices range from 0 to 3 (or, more descriptively, xα ranges over the set {ct,x,y,z}), where c is the speed of light in free space. The first tensor equation corresponds to four scalar equations, one for each value of β. The second tensor equation actually corresponds to 43 = 64 different scalar equations, but only four of these are independent.

For convenience, professionals often write the 4-gradient (that is, the derivative with respect to x) using abbreviated notations; for instance,

${\partial F^{\alpha\beta}\over \partial x^\gamma} \, \stackrel{\mathrm{def}}{=} \, \partial_\gamma F^{\alpha\beta} \, \stackrel{\mathrm{def}}{=} \, {F^{\alpha\beta}}_{,\gamma} \,.$

Using the latter notation, Maxwell's equations can be written as ${F^{\beta \alpha}}_{,\alpha} = \mu_0 J^\beta$ and $\epsilon^{\alpha\beta\gamma\delta} {F_{\alpha\beta,\gamma}}=0\ .$

## Continuity equation

The continuity equation which expresses the fact that charge is conserved is:

${J^{\alpha}}_{,\alpha} \, \stackrel{\mathrm{def}}{=} \, \partial_{\alpha} J^{\alpha} \, = \, 0 \,.$

## Lorentz force

Fields are detected by their effect on the motion of matter. Electromagnetic fields affect the motion of particles through the Lorentz force. Using the Lorentz force, Newton's law of motion can be written in relativistic form using the field strength tensor as[1]

$\frac{d p_{\alpha}}{d \tau} \, = q \, F_{\alpha \beta} \, u^\beta$

where p is the four-momentum (see above), q is the charge, u is the four-velocity (see above), and τ is the particle's proper time.

In terms of (normal) time instead of proper time, the equation is

${ d p_{\alpha} \over { d t } } = q \, F_{\alpha \beta} \, \frac{d x^\beta}{d t} \,.$

In a continuous medium, the 3D density of force combines with the density of power to form a covariant 4-vector, $f_{\mu} \,.$ The spatial part is the result of dividing the force on a small cell (in 3-space) by the volume of that cell. The time component is −1/c times the power transferred to that cell divided by the volume of the cell. The density of Lorentz force is the part of the density of force due to electromagnetism. Its spatial part is $\mathbf{f} = \rho \mathbf{E} + \mathbf{J} \times \mathbf{B}$. In manifestly covariant notation it becomes:

$f_{\mu} = F_{\mu\nu}J^{\nu} .\!$

## Differential equation for electromagnetic stress-energy tensor

The electromagnetic stress-energy tensor (defined above) satisfies the following differential equation, relating it to the electromagnetic tensor and the current four-vector

$\eta_{\alpha \nu} { T^{\nu \beta } }_{,\beta} + F_{\alpha \beta} J^{\beta} = 0 \,$

which expresses the conservation of linear momentum and energy by electromagnetic interactions.

## Lorenz gauge condition

The Lorenz gauge condition is a Lorentz-invariant gauge condition. (This can be contrasted with other gauge conditions such as the Coulomb gauge, which if it holds in one inertial frame will generally not hold in any other.) It is expressed in terms of the four-potential as follows:

$\eta^{\alpha \nu} \, \partial_{\alpha} A_{\nu} = 0 \,.$

### Maxwell's equations in the Lorenz gauge

In the Lorenz gauge, Maxwell's equations for a vacuum can be written as:

$\eta^{\sigma \nu} \, \Box A_{\nu} = - \mu_{0} \, J^{\sigma}$

where $\Box$ denotes the d'Alembertian.

## Bound current

In order to solve the equations of electromagnetism given here, it is necessary to add information about how to calculate the electric current, $J^{\alpha} \,.$ Frequently, it is convenient to separate the current into two parts, the free current and the bound current, which are modeled by different equations.

$J^{\alpha} = {J^{\alpha}}_{\text{free}} + {J^{\alpha}}_{\text{bound}} \,.$

The bound current is derived from the magnetization and electric polarization which form an antisymmetric contravariant magnetization-polarization tensor

$\mathcal{M}^{\mu \nu} = \begin{pmatrix} 0 & -P_xc & -P_yc & -P_zc \ P_xc & 0 & M_z & -M_y \ P_yc & -M_z & 0 & M_x \ P_zc & M_y & -M_x & 0 \end{pmatrix}$

which is determines the bound current so

${J^{\mu}}_{\text{bound}} = \partial_{\nu} \mathcal{M}^{\mu \nu} \,.$

If this is combined with $F^{\mu \nu} \,,$ we get the antisymmetric contravariant electromagnetic displacement tensor which combines the electric displacement $[D_x,D_y,D_z] \!$ and the magnetic field $[H_x,H_y,H_z] \,$ as follows

$\mathcal{D}^{\mu \nu} = \begin{pmatrix} 0 & D_xc & D_yc & D_zc \ -D_xc & 0 & H_z & -H_y \ -D_yc & -H_z & 0 & H_x \ -D_zc & H_y & -H_x & 0 \end{pmatrix}.$

They are related by

$\mathcal{D}^{\mu \nu} = \frac{1}{\mu_{0}} F^{\mu \nu} - \mathcal{M}^{\mu \nu} \,$

which is equivalent to the constitutive equations $\mathbf{D} = \epsilon_0 \mathbf{E} + \mathbf{P} \,$ and $\mathbf{H} = \frac{1}{\mu_{0}} \mathbf{B} - \mathbf{M} \,.$ And the result is that Ampère's law, $\mathbf{\nabla} \times \mathbf{H} = \mathbf{J}_{\text{free}} + \frac{\partial \mathbf{D}} {\partial t}$, and Gauss's law, $\mathbf{\nabla} \cdot \mathbf{D} = \rho_{\text{free}}$, combine to form:

${J^{\mu}}_{\text{free}} = \partial_{\nu} \mathcal{D}^{\mu \nu} \,.$

The bound current and free current as defined above are automatically and separately conserved

$\partial_{\mu} {J^{\mu}}_{\text{bound}} = 0 \,$
$\partial_{\mu} {J^{\mu}}_{\text{free}} = 0 \,.$

Thus we have reduced the problem of modeling the current, $J^{\alpha}\,,$ to two (hopefully) easier problems — modeling the free current, ${J^{\alpha}}_{\text{free}}\,,$ and modeling the magnetization and polarization, $\mathcal{M}^{\alpha \beta}\,.$ For example, in the simplest materials at low frequencies, one has

$\mathbf{J}_{\text{free}} = \sigma \mathbf{E} \,$
$\mathbf{P} = \epsilon_0 \chi_e \mathbf{E} \,$
$\mathbf{M} = \chi_m \mathbf{H} \,$

where one is in the instantaneously-comoving inertial frame of the material, σ is its electrical conductivity, χe is its electric susceptibility, and χm is its magnetic susceptibility.

## Lagrangian for classical electrodynamics

In a vacuum, the Lagrangian for classical electrodynamics (in joules/meter3) is

$\mathcal{L} \, = \, \mathcal{L}_{\mathrm{field}} + \mathcal{L}_{\mathrm{int}} = - \frac{1}{4 \mu_0} F^{\alpha \beta} F_{\alpha \beta} + A_{\alpha} J^{\alpha} \,.$

In the interaction term, the four-current should be understood as an abbreviation of many terms expressing the electric currents of other charged fields in terms of their variables; the four-current is not itself a fundamental field.

If we separate free currents from bound currents, the Lagrangian becomes

$\mathcal{L} \, = \, - \frac{1}{4 \mu_0} F^{\alpha \beta} F_{\alpha \beta} + A_{\alpha} J^{\alpha}_{\text{free}} + \frac12 F_{\alpha \beta} \mathcal{M}^{\alpha \beta} \,.$

The equivalent expression in non-relativistic vector notation is

$\mathcal{L} \, = \, \frac12 (\epsilon_{0} E^2 - \frac{1}{\mu_{0}} B^2) - \phi \, \rho_{\text{free}} + \mathbf{A} \cdot \mathbf{J}_{\text{free}} + \mathbf{E} \cdot \mathbf{P} + \mathbf{B} \cdot \mathbf{M} \,.$

## In general relativity

In general relativity, the metric, gαβ, is no longer a constant (ηαβ) but can vary from place to place and time to time. The metric tensor is the potential of the gravitational field. In general relativity, the equations of electromagnetism in a vacuum become:

$F_{\alpha \beta} \, = \, \partial_{\alpha} A_{\beta} \, - \, \partial_{\beta} A_{\alpha} \,$
$\mathcal{D}^{\mu\nu} \, = \, \frac{1}{\mu_{0}} \, g^{\mu\alpha} \, F_{\alpha\beta} \, g^{\beta\nu} \, \sqrt{-g} \,$
$J^{\mu} \, = \, \partial_\nu \mathcal{D}^{\mu \nu} \,$
$f_\mu \, = \, F_{\mu\nu} \, J^\nu \,$

where fμ is the density of Lorentz force, gαβ is the reciprocal of the metric tensor gαβ, and g is the determinant of the metric tensor. Notice that Aα and Fαβ are (ordinary) tensors while $\mathcal{D}^{\mu\nu}$, Jμ, and fμ are tensor densities of weight +1. All derivatives are partial derivatives — if one replaced them with covariant derivatives, the extra terms thereby introduced would cancel out.

## Notes and references

1. ^ The assumption is made that no forces other than those originating in E and B are present, that is, no gravitational, weak or strong forces.