Gain: Wikis

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In electronics, gain is a measure of the ability of a circuit (often an amplifier) to increase the power or amplitude of a signal. It is usually defined as the mean ratio of the signal output of a system to the signal input of the same system. It may also be defined on a logarithmic scale, in terms of the decimal logarithm of the same ratio ("dB gain").

Thus, the term gain on its own is ambiguous. For example, "a gain of five" may imply that either the voltage, current or the power is increased by a factor of five. Furthermore, the term gain is also applied in systems such as sensors where the input and output have different units; in such cases the gain units must be specified, as in "5 microvolts per photon" for the responsivity of a photosensor.

In laser physics, gain may refer to the increment of power along the beam propagation in a gain medium, and its dimension is m-1 (inverse meter) or 1/meter.

Logarithmic units and decibels

Power gain

Power gain, in decibels (dB), is defined by the 10 log rule as follows: $\text{Gain}=10 \log \left( {\frac{P_{out}}{P_{in}}}\right)\ \mathrm{dB}$

where Pin and Pout are the input and output powers respectively.

A similar calculation can be done using a natural logarithm instead of a decimal logarithm. The result is then in nepers instead of decibels.

Voltage gain

When power gain is calculated using voltage instead of power, making the substitution (P=V 2/R), the formula is: $\text{Gain}=10 \log{\frac{(\frac{{V_{out}}^2}{R_{out}})}{(\frac{{V_{in}}^2}{R_{in}})}}\ \mathrm{dB}$

In many cases, the input and output impedances are equal, so the above equation can be simplified to: $\text{Gain}=10 \log \left( {\frac{V_{out}}{V_{in}}} \right)^2\ \mathrm{dB}$

and then the 20 log rule: $\text{Gain}=20 \log \left( {\frac{V_{out}}{V_{in}}} \right)\ \mathrm{dB}$

This simplified formula is used to calculate a voltage gain in decibels, and is equivalent to a power gain only if the impedances at input and output are equal.

Current gain

In the same way, when power gain is calculated using current instead of power, making the substitution (P=I 2R), the formula is: $\text{Gain}=10 \log { \left( \frac { {I_{out}}^2 R_{out}} { {I_{in}}^2 R_{in} } \right) } \ \mathrm{dB}$

In many cases, the input and output impedances are equal, so the above equation can be simplified to: $\text{Gain}=10 \log \left( {\frac{I_{out}}{I_{in}}} \right)^2\ \mathrm{dB}$

and then: $\text{Gain}=20 \log \left( {\frac{I_{out}}{I_{in}}} \right)\ \mathrm{dB}$

This simplified formula is used to calculate a current gain in decibels, and is equivalent to the power gain only if the impedances at input and output are equal.

Example

Q. An amplifier has an input impedance of 50 ohms and drives a load of 50 ohms. When its input (Vin) is 1 volt, its output (Vout) is 10 volts. What are its voltage gain and power gain?

A. Voltage gain is simply: $\frac{V_{out}}{V_{in}}=\frac{10}{1}=10\ \mathrm{V/V}.$

The units V/V are optional, but make it clear that this figure is a voltage gain and not a power gain. Using the expression for power, P = V2/R, the power gain is: $\frac{V_{out}^2/50}{V_{in}^2/50}=\frac{V_{out}^2}{V_{in}^2}=\frac{10^2}{1^2}=100\ \mathrm{W/W}.$

Again, the units W/W are optional. Power gain is more usually expressed in decibels, thus: $G_{dB}=10 \log G_{W/W}=10 \log 100=10 \times 2=20\ \mathrm{dB}.$

A gain of factor 1 (equivalent to 0 dB) where both input and output are at the same voltage level and impedance is also known as unity gain. This article incorporates public domain material from the General Services Administration document "Federal Standard 1037C".

In electronics, gain is a measure of the ability of a circuit (often an amplifier) to increase the power or amplitude of a signal from the input to the output. It is usually defined as the mean ratio of the signal output of a system to the signal input of the same system. It may also be defined on a logarithmic scale, in terms of the decimal logarithm of the same ratio ("dB gain").

Thus, the term gain on its own is ambiguous. For example, "a gain of five" may imply that either the voltage, current or the power is increased by a factor of five, although most often this will mean a voltage gain of five for audio and general purpose amplifiers, especially operational amplifiers, but a power gain for RF amplifiers, and for directional aerials will refer to a signal power change compared with a simple dipole. Furthermore, the term gain is also applied in systems such as sensors where the input and output have different units; in such cases the gain units must be specified, as in "5 microvolts per photon" for the responsivity of a photosensor. The "gain" of a Bipolar transistor normally refers to forward current transfer ratio, either hFE ("Beta", the static ratio of Ic divided by Ib at some operating point), or sometimes hfe (the small-signal current gain, the slope of the graph of Ic against Ib at a point).

In laser physics, gain may refer to the increment of power along the beam propagation in a gain medium, and its dimension is m-1 (inverse meter) or 1/meter.

Logarithmic units and decibels

Power gain

Power gain, in decibels (dB), is defined by the 10 log rule as follows:

$\text\left\{Gain\right\}=10 \log \left\left( \left\{\frac\left\{P_\left\{\mathrm\left\{out\right\}\right\}\right\}\left\{P_\left\{\mathrm\left\{in\right\}\right\}\right\}\right\}\right\right)\ \mathrm\left\{dB\right\}$

where Pin and Pout are the input and output powers respectively.

A similar calculation can be done using a natural logarithm instead of a decimal logarithm, and without the factor of 10, resulting in nepers instead of decibels:

$\text\left\{Gain\right\} = \ln\left\left( \left\{\frac\left\{P_\left\{\mathrm\left\{out\right\}\right\}\right\}\left\{P_\left\{\mathrm\left\{in\right\}\right\}\right\}\right\}\right\right)\, \mathrm\left\{Np\right\}$

Voltage gain

When power gain is calculated using voltage instead of power, making the substitution (P=V 2/R), the formula is:

$\text\left\{Gain\right\}=10 \log\left\{\frac\left\{\left(\frac\left\{\left\{V_\left\{out\right\}\right\}^2\right\}\left\{R_\left\{out\right\}\right\}\right)\right\}\left\{\left(\frac\left\{\left\{V_\left\{in\right\}\right\}^2\right\}\left\{R_\left\{in\right\}\right\}\right)\right\}\right\}\ \mathrm\left\{dB\right\}$

In many cases, the input and output impedances are equal, so the above equation can be simplified to:

$\text\left\{Gain\right\}=10 \log \left\left( \left\{\frac\left\{V_\left\{out\right\}\right\}\left\{V_\left\{in\right\}\right\}\right\} \right\right)^2\ \mathrm\left\{dB\right\}$

and then the 20 log rule:

$\text\left\{Gain\right\}=20 \log \left\left( \left\{\frac\left\{V_\left\{out\right\}\right\}\left\{V_\left\{in\right\}\right\}\right\} \right\right)\ \mathrm\left\{dB\right\}$

This simplified formula is used to calculate a voltage gain in decibels, and is equivalent to a power gain only if the impedances at input and output are equal.

Current gain

In the same way, when power gain is calculated using current instead of power, making the substitution (P=I 2R), the formula is:

$\text\left\{Gain\right\}=\left\{ \left\left( \frac \left\{ \left\{I_\left\{collector\right\}\right\} \right\} \left\{ \left\{I_\left\{base\right\}\right\} \right\} \right\right) \right\} \ \\right\}$

In many cases, the input and output impedances are equal, so the above equation can be simplified to:

$\text\left\{Gain\right\}=10 \log \left\left( \left\{\frac\left\{I_\left\{out\right\}\right\}\left\{I_\left\{in\right\}\right\}\right\} \right\right)^2\ \mathrm\left\{dB\right\}$

and then:

$\text\left\{Gain\right\}=20 \log \left\left( \left\{\frac\left\{I_\left\{out\right\}\right\}\left\{I_\left\{in\right\}\right\}\right\} \right\right)\ \mathrm\left\{dB\right\}$

This simplified formula is used to calculate a current gain in decibels, and is equivalent to the power gain only if the impedances at input and output are equal.

The "current gain" of a bipolar transistor, hFE or hfe, is normally given as a dimensionless number, the ratio of Ic to Ib (or slope of the Ic vs Ib graph, for hfe).

Example

Q. An amplifier has an input impedance of 50 ohms and drives a load of 50 ohms. When its input ($V_\left\{in\right\}$) is 1 volt, its output ($V_\left\{out\right\}$) is 10 volts. What are its voltage gain and power gain?

A. Voltage gain is simply:

$\frac\left\{V_\left\{out\right\}\right\}\left\{V_\left\{in\right\}\right\}=\frac\left\{10\right\}\left\{1\right\}=10\ \mathrm\left\{V/V\right\}.$

The units V/V are optional, but make it clear that this figure is a voltage gain and not a power gain. Using the expression for power, P = V2/R, the power gain is:

$\frac\left\{V_\left\{out\right\}^2/50\right\}\left\{V_\left\{in\right\}^2/50\right\}=\frac\left\{V_\left\{out\right\}^2\right\}\left\{V_\left\{in\right\}^2\right\}=\frac\left\{10^2\right\}\left\{1^2\right\}=100\ \mathrm\left\{W/W\right\}.$

Again, the units W/W are optional. Power gain is more usually expressed in decibels, thus:

$G_\left\{dB\right\}=10 \log G_\left\{W/W\right\}=10 \log 100=10 \times 2=20\ \mathrm\left\{dB\right\}.$

A gain of factor 1 (equivalent to 0 dB) where both input and output are at the same voltage level and impedance is also known as unity gain.

Source material

Up to date as of January 22, 2010

From Wikisource

 Gain by Richard Aldington

Let not the jesting bitter gods
Who sit so goldenly aloof from us
Mock us too deeply,
Let them not boast they hold alone
The reins of pleasure, the delight of lust—
We that are but air and dust
Moistening that dust a little with old wine
And kindling the air with fire and love
Have burned an hour or two with blossoming pangs,
And, leaning on soft breasts made keen with love,
And murmuring fierce words of ending bliss,
Have gathered turn by turn unto our lips
The twin wild roses of delight,
The quickflower-flames that sear into the soul
Sharp wounds of pleasure and extreme desire.